Enter the radius of the base and the height of the cylinder. The surface area (S = 2πr(r + h)) is shown with its parts (base area and lateral area), along with conversions between cm² and m².
Table of Contents
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What you can do on this page
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What is this calculation used for?
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How to Use
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Formulas and figures
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Symbols and terms
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Good to know before you start
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How to calculate it in Excel
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How to calculate it in Google Sheets
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How to calculate it in Python
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How to write it in LaTeX and other math languages (copy and paste)
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How to have ChatGPT do the calculation
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DataChef Features
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Related Features
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NumberChef Calculators List
What you can do on this page
- Enter the radius of the base and the height, and the surface area of the cylinder (\(S = 2\pi r(r+h)\)) is calculated on the spot
- The result also breaks the total down into the base area (\(\pi r^2\)), the two bases together and the lateral area (\(2\pi rh\)), so you can see where each part comes from
- The result also shows the area in another unit: square feet (ft²) if you enter inches, and square inches (in²) if you enter feet. Switch "Units" to Metric to use cm² and m² instead
- The result is also drawn as a 3D shape. Turn it with the mouse or a swipe to check its shape
- A plain-language explanation of the formulas and copy-and-paste formulas for Excel, Google Sheets and Python are all on this page
What is this calculation used for?
A 12-ounce soda can is close to a cylinder with a radius of 1.3 in and a height of 4.8 in. Its surface area is \(2\pi \times 1.3 \times (1.3 + 4.8) \approx 49.8\,\mathrm{in^2}\), and the metal in one can is roughly this area.
Billions of cans are made every year, so choosing a shape with less surface area for the same volume (the right balance of radius and height) saves a lot of material. This formula is a basic tool in can design.
A 55-gallon drum, with a radius of about 11.25 in and a height of about 33.5 in, has a surface area of \(2\pi \times 11.25 \times (11.25 + 33.5) \approx 3163\,\mathrm{in^2}\), or about 22 ft².
Paint cans list how many square feet they cover, so once you know the surface area you can work out how much to buy. For rust-proofing and waterproofing jobs too, the estimate starts with the surface area.
To wrap a pipe with an outside diameter of 2 in (radius 1 in, or 1/12 ft) that runs 30 ft, the insulation covers the lateral area, \(2\pi \times \tfrac{1}{12} \times 30 \approx 15.7\,\mathrm{ft^2}\) (the ends of the pipe connect to other pipes, so only the side counts).
Jobs such as insulating hot water pipes or preventing condensation use this lateral area formula to estimate materials. It is a classic case of using only the part of the surface area you need.
An 8-inch round cake (radius 4 in) that is 4 in tall has a lateral area of \(2\pi \times 4 \times 4 \approx 100.5\,\mathrm{in^2}\), and a collar wrapped around its side must be as long as the circumference, \(2\pi \times 4 \approx 25.1\) in.
Thinking of the side as a rectangle (width = circumference, height = height), just as on this page, tells you how much acetate or chocolate you need for the decoration.
To make a cover for a water bottle with a radius of 1.5 in and a height of 8 in, the fabric for the side is a rectangle about 9.4 in wide (the circumference) and 8 in tall, with an area of \(2\pi \times 1.5 \times 8 \approx 75.4\,\mathrm{in^2}\). The bottom needs one circle, about \(\pi \times 1.5^2 \approx 7.1\,\mathrm{in^2}\) (add seam allowances in practice).
For round pouches, pencil cup covers and anything else shaped like a cylinder, the idea of the net goes straight into making the pattern.
Formulas and figures
Symbols and terms
Symbols
| \(S\) | ess | A common symbol for area. On this page it stands for the surface area of the cylinder (the total area of all its faces). |
| \(B\) | bee | The base area (the area of one base circle), from the first letter of "base". It is found with the circle area formula \(\pi r^2\). |
| \(L\) | capital L | The lateral area (the area of the whole side), from the first letter of "lateral". It is circumference × height = \(2\pi rh\). |
| \(r\) | ar | The radius of the base circle (the distance from its center to its edge), from the first letter of "radius". It is half the diameter. |
| \(h\) | aitch | The height of the cylinder (the straight distance from the bottom face to the top face), from the first letter of "height". |
| \(\pi\) | pi | The Greek letter for the ratio of a circle's circumference to its diameter. It goes on forever as \(3.14159\ldots\), and 3.14 is a common rounded value. |
| \(r^2\) | r squared | The number \(r\) multiplied by itself (\(r \times r\)). The small raised 2 is an exponent that shows how many times the number is used as a factor. |
| \(2\pi r\) | two pi r | The circumference of the base circle (the distance around it): diameter (\(2r\)) × pi. It is the width of the rectangle you get when you unroll the side. |
| \(\mathrm{in^2}\) | square inches | A unit of area. A square that is 1 inch on each side has an area of 1 in². |
| \(\mathrm{ft^2}\) | square feet | A unit of area. A square that is 1 foot on each side has an area of 1 ft². \(1\,\mathrm{ft^2} = 144\,\mathrm{in^2}\). |
Terms
| cylinder | A straight solid with circular bases, where every slice across it is a circle of the same size. Cans, drums and paper towel tubes are all around us. |
| surface area | The total area of the outside of a solid. For a cylinder, it is the two bases (top and bottom) plus the side. It tells you how much material covers the surface, such as wrapping or paint. |
| base | The top and bottom faces of a prism or cylinder. A cylinder has two circles of the same size, one at the top and one at the bottom, and both are called bases. |
| base area | The area of a base. For a cylinder the base is a circle, so the base area comes from the circle area formula \(\pi r^2\) (\(\pi\) × radius × radius). |
| lateral surface | The side of a solid, all the way around. The side of a cylinder is one curved surface that becomes a rectangle when you cut it straight down and unroll it. |
| lateral area | The area of the whole side. For a cylinder, it is the area of the unrolled rectangle: circumference × height = \(2\pi rh\). |
| net | The flat shape you get by cutting a solid open and laying it out. The net of a cylinder is 2 circles plus 1 rectangle, and the surface area is the total area of the net. |
| circumference | The distance around a circle: diameter × pi = \(2\pi r\). The width of the unrolled side of a cylinder is exactly the circumference. |
| pi | The number of times a circle's diameter fits around its circumference. It is the same for every circle, is written \(\pi\), and is about 3.14. |
| factoring out a common factor | Pulling a factor that every term shares out in front of parentheses. Taking the common \(2\pi r\) out of \(2\pi r^2 + 2\pi rh\) gives \(2\pi r(r+h)\). |
| unit conversion | Writing the same amount in a different unit. For area, the key point is that the area factor is the length factor squared (1 ft = 12 in, so 1 ft² = 144 in²). |
Good to know before you start
Here is what helps you use the calculation on this page with real understanding, not just by pressing the button.
| Area and circumference of a circle (Grade 7) |
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| Area of a rectangle (Grades 3–4) |
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| Nets (Grades 6–7) |
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| Units of area (Grades 3–5) |
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| Pi and algebraic expressions (Grades 7–8) |
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How to calculate it in Excel
| Radius of the base r (in) | 3 |
| Height h (in) | 4 |
| Both bases, 2πr² (in²) | =2*PI()*B1^2 |
| Lateral area, 2πrh (in²) | =2*PI()*B1*B2 |
| Surface area (in²) | =B3+B4 |
| Radius of the base r (in) | 3 |
| Base area, πr² (in²) | =PI()*B1^2 |
| Radius of the base r (in) | 3 |
| Height h (in) | 4 |
| Lateral area, 2πrh (in²) | =2*PI()*B1*B2 |
| Radius of the base r (in) | 3 |
| Height h (in) | 4 |
| Surface area, 2πr(r+h) (in²) | =2*PI()*B1*(B1+B2) |
| Surface area in in² | 3163 |
| Surface area in ft² | =B1/144 |
In a formula, "PI()" is the Excel function that returns pi (3.14159…), "B1" and "B2" mean "use the number in that cell", "*" is multiplication, "/" is division and "^" is an exponent (how many times to multiply).
In the first table, for example, B3 shows about 56.549, B4 about 75.398 and B5 about 131.947 (in², since the inputs are in inches). B3 of the fourth table shows the same 131.947, and the fifth table shows about 21.97 (ft²) in B2. Just replace the input numbers with the size of your own cylinder.
How to calculate it in Google Sheets
| Radius of the base r (in) | 3 |
| Height h (in) | 4 |
| Both bases, 2πr² (in²) | =2*PI()*B1^2 |
| Lateral area, 2πrh (in²) | =2*PI()*B1*B2 |
| Surface area (in²) | =B3+B4 |
| Radius of the base r (in) | 3 |
| Base area, πr² (in²) | =PI()*B1^2 |
| Radius of the base r (in) | 3 |
| Height h (in) | 4 |
| Lateral area, 2πrh (in²) | =2*PI()*B1*B2 |
| Radius of the base r (in) | 3 |
| Height h (in) | 4 |
| Surface area, 2πr(r+h) (in²) | =2*PI()*B1*(B1+B2) |
| Surface area in in² | 3163 |
| Surface area in ft² | =B1/144 |
How to calculate it in Python
import math
radius = 3 # radius of the base (inches in this example)
height = 4 # height (same unit as the radius)
base_area = math.pi * radius ** 2 # base area (one circle, in2 in this example)
bases_area = base_area * 2 # both bases
lateral_area = 2 * math.pi * radius * height # lateral area (circumference x height)
surface_area = bases_area + lateral_area # surface area of the cylinder (= 2*pi*r*(r+h))
print(f"Base area (one circle): {base_area} in2")
print(f"Both bases: {bases_area} in2")
print(f"Lateral area: {lateral_area} in2")
print(f"Surface area: {surface_area} in2")
How to write it in LaTeX and other math languages (copy and paste)
S = B × 2 + L
S = B \times 2 + L
<math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
<mrow>
<mi>S</mi>
<mo>=</mo>
<mi>B</mi>
<mo>×</mo>
<mn>2</mn>
<mo>+</mo>
<mi>L</mi>
</mrow>
</math>
S = B xx 2 + L
sBase*2 + sSide
S := sBase*2 + sSide;
S = s_base*2 + s_side;
S = B × 2 + L
B = π × r²
B = \pi r^{2}
<math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
<mrow>
<mi>B</mi>
<mo>=</mo>
<mi>π</mi>
<mo>⁢</mo>
<msup><mi>r</mi><mn>2</mn></msup>
</mrow>
</math>
B = pi r^2
Pi*r^2
sBase := Pi*r^2;
s_base = pi*r^2;
B = πr^2
L = 2 × π × r × h
L = 2\pi r h
<math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
<mrow>
<mi>L</mi>
<mo>=</mo>
<mn>2</mn>
<mo>⁢</mo>
<mi>π</mi>
<mo>⁢</mo>
<mi>r</mi>
<mo>⁢</mo>
<mi>h</mi>
</mrow>
</math>
L = 2 pi r h
2*Pi*r*h
sSide := 2*Pi*r*h;
s_side = 2*pi*r*h;
L = 2πrh
S = 2 × π × r × (r + h)
S = 2\pi r(r+h)
<math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
<mrow>
<mi>S</mi>
<mo>=</mo>
<mn>2</mn>
<mo>⁢</mo>
<mi>π</mi>
<mo>⁢</mo>
<mi>r</mi>
<mo>⁢</mo>
<mrow><mo>(</mo><mi>r</mi><mo>+</mo><mi>h</mi><mo>)</mo></mrow>
</mrow>
</math>
S = 2 pi r (r + h)
2*Pi*r*(r + h)
S := 2*Pi*r*(r + h);
S = 2*pi*r*(r + h);
S = 2πr(r + h)
S[ft²] = S[in²] ÷ 144
S_{\mathrm{ft^2}} = S_{\mathrm{in^2}} \div 144
<math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
<mrow>
<msub><mi>S</mi><mrow><msup><mi mathvariant="normal">ft</mi><mn>2</mn></msup></mrow></msub>
<mo>=</mo>
<msub><mi>S</mi><mrow><msup><mi mathvariant="normal">in</mi><mn>2</mn></msup></mrow></msub>
<mo>÷</mo>
<mn>144</mn>
</mrow>
</math>
S_(ft^2) = S_(in^2) -: 144
sIn2/144
sFt2 := sIn2/144;
s_ft2 = s_in2/144;
S(ft²) = S(in²)/144
How to have ChatGPT do the calculation
You are a math calculation assistant. Do the following calculation by actually running Python code, and base your answer only on the numbers from the execution result (do not answer by mental math or guessing). A cylinder has a base radius of 3 inches and a height of 4 inches. Find each of the following: 1. The base area (one circle) in square inches (in²) 2. The lateral area in square inches 3. The surface area of the cylinder (two bases + side) in square inches Show the formulas you used and the numbers from the execution result.
How to Use
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1Enter your numbersType the numbers you want to calculate with into the input fields
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2CalculatePress the "Calculate" button
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3Check the resultThe result appears on the spot. The same page also explains the idea behind the calculation and the formula
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